ENCE 433 Dr. Alba Torrents
EXAMINATION 2 "SOLUTION" Fall 1996
Thursday, October 31
1.
|
CT |
ACYDITY |
|
|
NaOH |
--- |
¯ |
|
HCl |
--- |
|
|
CO2 |
|
--- |
|
NaHCO3 |
|
|
|
Na2CO3 |
|
|
|
NaCl |
--- |
--- |
|
NH3 |
--- |
¯ |
2.
Alk = [Na+] - [H2PO4-] =
3 [Na3PO4] -1 [Na3PO4] = 2
[Na3PO4] = 2x10-4.5
3.
(a)
pH ~ 9.5 so we need to add a base.
At this pH most of CT is as HCO3-,
so we need to titrate it all to CO3-2; We need to
add the same number of moles of an strong base.
4. (a)
the number of moles will depend on the desire molarity of the final
solution. If X Molar
X = [Na2CO3] + [NaHCO3]
(b) If equilibrated with the atmosphere, one can use just the salt as
NaHCO3 will be form by Na2CO3 + CO2
NaHCO3