ENCE 433 Dr. Alba Torrents

EXAMINATION 2 "SOLUTION" Fall 1996

Thursday, October 31

1.

CT

ACYDITY

NaOH

---

¯

HCl

---

­

CO2

­

---

NaHCO3

­

­

Na2CO3

­

­

NaCl

---

---

NH3

---

¯

2.

  1. Alk = [Na+] = 10-3
  2. Alk = -[Cl-] = -10-3

Alk = [Na+] - [H2PO4-] = 3 [Na3PO4] -1 [Na3PO4] = 2 [Na3PO4] = 2x10-4.5

3.

(a)


  1. pH of the mixture can be estimated using the Deffeyes diagram:

pH ~ 9.5 so we need to add a base.

At this pH most of CT is as HCO3-, so we need to titrate it all to CO3-2; We need to add the same number of moles of an strong base.

4. (a)


the number of moles will depend on the desire molarity of the final solution. If X Molar

X = [Na2CO3] + [NaHCO3]


(b) If equilibrated with the atmosphere, one can use just the salt as NaHCO3 will be form by Na2CO3 + CO2 NaHCO3